If an equation is given in slope-intercept form (y = mx + b), it is very easy to find the y-intercept because by definition the y-intercept of an equation in slope-intercept for is the point (0,b). In other words, if a linear equation or function is in slope-intercept form (or solved for y), the y-intercept is a point that has an x component of 0 (x = 0), and the y-component is the value that is not attached (multiplying) any variable. It is the constant b. Examples...
If an equation is given in standard form (Ax + By = C), there are two possibilities (putting the equation in slope-intercept form by solving for y and/or just setting x to 0 and solving for y). For the purposes of this conversation, I will look at the second option and set x = 0 and solve for y. Since I set x to 0, my resulting y-intercept is point that has an x-component of 0. The y-component is found by solving the resulting equation for y. Examples...
If only a graph is given, you are simply looking for the points where the graph crosses the y-axis (vertical axis). Again, the point is of the form (0, ?) where the question mark is replaced by the value(s) of y at which the graph crosses. Examples...

| y-intercept = (0,-2) | y-intercept = (0,3) | y-intercepts = (0,5) and (0,-1) |
If an equation is given, there are two possibilities (solving the equation for x and/or just setting y to 0 and solving for x). For the purposes of this conversation, I will look at the second option and set y = 0 and solve for x. Since I set y to 0, my resulting x-intercept is point that has a y-component of 0. The x-component is found by solving the resulting equation for x. Examples...
If only a graph is given, you are simply looking for the points where the graph crosses the x-axis (horizontal axis). Again, the point is of the form (?,0) where the question mark is replaced by the value(s) of x at which the graph crosses. Examples...

| x-intercept = (4,0) | x-intercept = (0,0) | x-intercepts = (-4,0) , (-1,0) and (5,0) |